search for ccna answer

Showing posts with label CN stuff. Show all posts
Showing posts with label CN stuff. Show all posts

Sunday, May 13, 2012

UCEN 3133 Advanced Computer Networks - Tutorial 2 - Year 2012

Tutorial 2 – MPLS Overview

1. Sketch the diagram of an Edge LSR (Label Switching Router). Identify 3 components that are important with respect to label switching at the periphery of an autonomous MPLS network, and briefly explain how they function.





     (i)            The Forwarding Information Base (FIB) is a standard IP forwarding table extended with labelling information. It allows labelled packets from within the MPLS core network to routed forwards as pure IP packets
   (ii)            Label Information Base (LIB) - holds all labels assigned by this LSR and the  mappings of these labels to labels received from any neighboring LSRs, during the process of label binding exchange.
 (iii)            Label Forwarding Information Base (LFIB) is used during the actual forwarding of labelled packets and holds only labels that are in use currently


2. Explain how labels can be useful as a preliminary measure  towards the enforcement of some form of QOS guarantee in a MPLS, making reference in your answer to Forward Equivalence Class (FEC)

Forwarding Equivalence Class (FECs) is a way of grouping incoming packets in some way so that all packets identified with a particular FEC are treated in the same manner, for example being switched over the same path (LSP). This allows some form of QOS to be enforced on the LSRs of the label switched path (LSP) that the packets flow through. Labels are associated with each particular FEC, and the FEC is established once at the entry of the IP packet into an ingress LSR.

3. Give examples of 3 items that can be used in classifying a Forward Equivalence Class (FEC)

     (i)            A specific source or destination IP network address
   (ii)            A specific class of traffic (e.g. interactive voice, streaming media) data within the packet
 (iii)            The particular interface on a router which the packet arrives on

4. Explain what is meant by label disposition or imposition with respect to an edge LSR.

Label imposition is the act of appending a label, or a stack of labels, to a packet in the ingress point of the MPLS domain. Label disposition is the act of removing the last label from a packet at the egress point before it is forwarded to a neighbor that is outside the MPLS domain.

5. Consider that an egress LSR in autonomous MPLS (AS 1) is communicating with its peer in another autonomous MPLS network (AS 2) using a suitable protocol (BGP for example). The process of negotiation between these peers results in a decision that exiting IP packets with a specific subnet prefix from the egress LSR in AS1 is to be routed along a specific Label Switched Path (LSP) in AS 2. Sketch an outline of how this might be accomplished using labels. What is the advantage of this approach ?

The ingress edge LSR at AS1 negotiates with the egress LSR of AS1, to append a label to all incoming packets into AS1. This label specifies that packets with a specific subnet prefix are meant to be switched immediately onwards to AS2 once they exit  from AS1. The AS1 ingress LSR builds a label stack by pushing another label corresponding to an LSP that terminates at the IP address of the AS1 egress LSR. This packet with two labels is forwarded along a LSP in AS1. All the other LSRs in the LSP in AS1 only perform switching on the top most label in the stack. Finally, at the egress LSR of AS1 this label is popped leaving the bottom label – which is used to forward the packet on to the ingress router of AS2

Monday, April 16, 2012

UCEN 3133 Advanced Computer Networks - Tutorial 1


1. Explain how connection oriented switching (as exemplified by technologies like ATM or MPLS) provides an advantage of speed over connectionless packet switching technologies (such as TCP/IP) ?

Connection oriented switching uses the label on a packet as an index into an internal table to forward the packets onwards. The process of indexing into a table is faster than searching a table (which is the mechanism used in routing), particularly when the indexing can be implemented in hardware
 
2. Describe briefly 4 underlying reasons why ATM was not adopted on a larger scale. What factor makes MPLS more attractive to a broader adoption in comparison to ATM ?

  1. Expense: ATM switches and NIC much more expensive than Ethernet: existing Ethernet equipment in IP networks could not be reused
  2. Connection set up latency: Since ATM is connection oriented, the packet request to set up a PVC has to pass through many switches before acknowledgment
  3. Cell overhead: the large ATM cell header provides a big overhead
  4. Specification of QOS requirements difficult: not all applications know beforehand the QOS that they require during a session.

MPLS was designed to build on top of the existing IP infrastructure (particularly layer 2 – Ethernet), rather than replace it completely – which makes it easier for companies with legacy IP infrastructure to migrate.

3. Explain how a Switched Virtual Circuit (SVC) established in an ATM network ?

  1. The host requiring a connection sends a  connection request to first ATM switch
  2. This ATM switch then finds path to destination and forwards request to all switches along path
  3. Each pair communicates with the next in sequence on path to choose matching VPI/VCI and store in respective tables.
  4. Only if all switches agree to establishing the SVC, is successful acknowledgement provided, otherwise request denied.
  5. The request setup SVC is done through signalling control and request messages, sent across reserved connections for control traffic


4. Briefly describe 3 advantages offered by switching across an IP infrastructure

  1. Faster forwarding because of indexing in place of routing table lookup
  2. Aggregated route information.  IP routing table look up once when packet arrives at edge router in ISP, and packet is assigned a label for further forwarding.
  3. Manage aggregate flows through a Service Level Agreement (SLA) easier with labels. Each label is equivalent to the Forward Equivalence Class (FEC)

5. Consider 2 hosts, X and Y,  in an ATM network with 3 intermediating ATM switches, A, B and C between them. The order of connection in a newly formed PVC is X -> A -> B-> C-> Y. Given below are the switching tables for all 3 switches:

Switch C

Old
VPI/VCI
Interface
New
VPI/VCI
0
0
5
1
0
3
2
1
2
3
1
4
4
2
1
5
0
0

Switch B

Old
VPI/VCI
Interface
New
VPI/VCI
0
1
0
1
0
5
2
0
4
3
0
1
4
2
2
5
0
3

Switch A

Old
VPI/VCI
Interface
New
VPI/VCI
0
0
5
1
0
1
2
1
3
3
2
2
4
0
4
5
1
0

Given that the VPI/VCI leading into Y has the value of 4, what is the value of the VPI/VCI at the initial end of X ?

Answer:

From Switch C table, the old VPI/VCI resulting in 4 going into Y is 3
From Switch B table, the old VPI/VCI resulting in 3 going into Switch C is 5
From Switch A table, the original VPI/VCI resulting in 5 going into Switch B is 0
Therefore, initial end of X has VPI/VCI of 0

Sunday, November 23, 2008

CCNA Module 2 : All Chapter

The "guide/hint":

Blog 1

Blog 2

Blog 3

For those who intended to get 100% in test, PLEASE refer the 3 site above and made a comparison, then only you will get totally 100%, juz like me :)

more site will be added ^^

Tuesday, October 7, 2008

Monday, April 14, 2008

CN PM coursework marks

Download Link

Thx to Cheese ! ^^

UNIVERSITI TUNKU ABDUL RAHMAN












FACULTY
FACULTY OF INFORMATION AND COMMUNICATION TECHNOLOGY
COURSE
BACHELOR OF INFORMATION TECHNOLOGY (HONS) COMMUNICATIONS AND NETWORKING
ACADEMIC YEAR 2007/08




SESSION
200801




YEAR
1




SEMESTER
2















Ujian Tugasan
Pembentangan Total (100%)
CN1 S2 T1 1 07UCB05688 16 39
27 82
CN1 S2 T1 2 07UCB06704 13 41
24 78
CN1 S2 T2 3 07UCB07574 10 28
24 62
CN1 S2 T1 4 07UCB06779 18 28
24 70
CN1 S2 T2 5 08UCB00588 16 39
26 81
CN1 S2 T1 6 07UCB05636 17 39
26 82
CN1 S2 T2 7 07UCB08709 9 28
26 63
CN1 S2 T1 8 07UCB04873 17 39
26 82
CN1 S2 T1 9 07UCB08481
28
24 52
CN1 S2 T2 10 07UCB06956 10 38
26 74
CN1 S2 T1 11 07UCB03118 18 28
26 72
CN1 S2 T2 12 07UCB08631 9 28
26 63
CN1 S2 T1 13 07UCB05515 10 28
24 62
CN1 S2 T1 14 07UCB08474 10 48
29 87
CN1 S2 T2 15 07UCB07633 19 48
29 96
CN1 S2 T2 16 07UCB07038 10 38
28 76
CN1 S2 T2 17 07UCB08755



0
CN1 S2 T1 18 07UCB03149 19 48
29 96
CN1 S2 T2 19 07UCB08760



0
CN1 S2 T1 20 07UCB06469 11 38
26 75
CN1 S2 T2 21 07UCB08751 9 28
28 65
CN1 S2 T1 22 07UCB05411 10 48
29 87
CN1 S2 T2 23 07UCB08746 15 28
26 69
CN1 S2 T1 24 07UCB06382 13

23 36
CN1 S2 T1 25 07UCB06705 9 41
24 74
CN1 S2 T2 26 07UCB08735 15 28
25 68
CN1 S2 T2 27 07UCB06776 9 41
24 74
CN1 S2 T2 28 07UCB07382 11 38
27 76
CN1 S2 T2 29 07UCB06440 18 28
24 70
CN1 S2 T2 30 07UCB05995 9 41
23 73
CN1 S2 T2 31 07UCB06778 11 38
27 76
CN1 S2 T2 32 07UCB06777 19 48
29 96
CN1 S2 T2 33 07UCB03036 17 39
26 82








































































































































































































Saturday, April 12, 2008

CN Final Tips!!

Hey guys and gals!
Check out final exam tips!

It is all here!
Thx to all who had provided these tips~
Especially to Mr Melvin!!

Let's Say : Aligato, Terima Kasih, Thank you, 谢谢 to him !

Cheer ~ good luck to everyone !
CN the best ~

Download Link

12/04 02:18 AM UPDATED

Tuesday, March 18, 2008

Hi to all CN Y1 S2 guys and gals - Database Test

Wow..
We meet again here ! :P
haha..

2morrow is our database test !
OMG ...
Me Still watching drama !!!
斗牛,要不要
erm.. not bad punya drama ...



ini...
ini...


...bodoh !

For those dude who are same as me (pretending 2morrow test is damn easy X.X)
Here is something that might be help in your database test :)
Check it out !
It is the Test Paper ..

Test Paper

Test Paper Solution
Dont doubt it , Download it, It will come out 2morrow !!!



Credits
Thx to our toudaizai :)

Email
bncteam4u@gmail.com












haha....
bohong lagi
apa macam ?

That test paper is last sem punya 2007 MAY paper...
:)

Monday, March 17, 2008

Hi to all CN Y1 S2 guys and gals - PART 2

Haha ...
part 1 seen like really helpful to all the CN ppl
^.^

So here is the part 2 :
Prac 6-10 Solution
No Password at all
Congratulations to those who success break the password on part 1 !
Erm... I think it is too simple
iz it ? :p


Note:
For those who had get the practical solution completely from here, I do hope that everybody should keep the voice down, it is not necessary to let as many people know, no need to talk around in UTAR campus. Hmm... if this thing let's those tutor know, hehe...maybe next time no more this kind of stuff share to all the CN people already liao lo !

apa macam ?
So, just share among the CN people , cause CN IS THE BEST :)






CN is the BEST!!!
CN is the BEST!!!
CN is the BEST!!!
CN is the BEST!!!
CN is the BEST!!!


Credits
Thx to uncle calvin :)
Thx to Ms.Priya :P















HaHa... Above that is not the file
Here is the right link :P
Prac 6-10 Solution

Sunday, March 16, 2008

Hi to all CN Y1 S2 guys and gals - PART 1

hi , hi , hi ...
=.=

erm...
actually nothing special la ~
juz wan you all to come to my blog
raise my blog traffic !


oh no ...
pls dont go ...
pls...
pls...

haha...
ok , let's talk serious

Below is the practical solution from prac1 - prac5
yoho ...
is full solution from lecturer
guess where i get it ???
shih...is a secret
Can you keep a secret ? ^.^

I hope those practical solution will help you all in the assginment ^.^


Credits
thx to uncle calvin :)





Prac 1 solution


Prac 2 solution


Prac 3 solution


Prac 4 solution
hehe...this put wrong, should be database lecturer , soli soli .. x.x

Prac 5 solution



erm...
due to some condition
prac 6 - 10 solution will upload before tuesday ^.^

If got any question, dont hesitate to let's us know
or juz leave comment here let us noe ^.^

aligato :)